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Author Topic: Regex validation help  (Read 1763 times)
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deAppel
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« on: December 03, 2007, 08:42:48 AM »

Hi,

I'm new with regex and i wanted to ask how to properly validate a string using regex?

I created a small demo here:
Code
GeSHi (java):
  1. class RegexString {
  2. public static void main(String[] args){
  3. String txt="abCD";
  4. String re1="[a-zA-Z]*";
  5. Pattern p = Pattern.compile(re1,Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
  6.  
  7. Matcher m = p.matcher(txt);
  8. if (m.find()){
  9. String text=m.group(0);
  10. System.out.print("String: "+text.toString());
  11. }
  12. else{
  13. System.out.print("Number");
  14. }
  15. }
  16. }
Created by GeSHI 1.0.7.20

Although it prints out the text i can't seem to "catch" a non string value and do something with it. How can i go to the else when the entered text in the txt string does not matches [a-zA-Z] ?

Thanks,

Ark
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« Reply #1 on: December 03, 2007, 01:55:24 PM »

Nevermind, its fixed. Instead of find() , I was recommended to use matches()

Code
GeSHi (java):
  1. import java.util.regex.Matcher;
  2. import java.util.regex.Pattern;
  3.  
  4. class RegexString {
  5. public static void main(String[] args){
  6. String txt="1234AB";
  7. String re1="^[0-9]{4}[a-z|A-Z]{2}$";
  8.  
  9. Pattern p = Pattern.compile(re1);
  10. Matcher m = p.matcher(txt);
  11. if (m.matches()){
  12. String text=m.group(0);
  13. System.out.print("Postcode: "+text.toString());
  14. }
  15. if (!m.matches()){
  16. System.out.print("Not a valid postcode.");
  17. }
  18. }
  19. }
  20.  
Created by GeSHI 1.0.7.20
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I was born into the Hakka lineage, A bloodline that
traces it's roots back to the original Han emperors of
China. During the rise of the 3 Kingdoms (China's
famous warring period), the Hans were overthrown
and exiled. Forced to flee, they headed south finding
refuge within the mountains of Guilin Province where
they lived under their new title, the Hakka and patiently
wait for their chance to return to the throne as the
Sons Of Heaven...
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« Reply #2 on: December 04, 2007, 10:36:29 AM »

An email validator using regex:

Code
GeSHi (java):
  1. import java.util.regex.*;
  2.  
  3. class regexSample
  4. {
  5.   public static void main(String args[])
  6.   {
  7.      //Input the string for validation
  8.      String email = "xyz@hotmail.com";
  9.  
  10.      //Set the email pattern string
  11.      Pattern p = Pattern.compile(".+@.+\\.[a-z]+");
  12.  
  13.      //Match the given string with the pattern
  14.      Matcher m = p.matcher(email);
  15.  
  16.      //check whether match is found
  17.      boolean matchFound = m.matches();
  18.  
  19.      if (matchFound)
  20.        System.out.println("Valid Email Id.");
  21.      else
  22.        System.out.println("Invalid Email Id.");
  23.   }
  24. }
Created by GeSHI 1.0.7.20

http://www.devx.com/tips/Tip/28334
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